x dy + 2y dx = 0
Dividing by 'xy', the two variables 'x' and 'y' are separated.
Integrating w.r.t. 'x'
2 log x | = | – log y + log c |
log x2 | = | log(c/y) |
x2 | = | c/y |
x | = | √(c/y) is the required solution. |
Differential Equation reducible to the variable separable type:
Solve = sin(x + y) + cos(x + y).
Sol: Put x + y = u then
= – 1 ------ (i)
The given eqn. (i) transforms to
– 1 = sin u + cos u
⇒ = 1 + sin u + cos u
Separating the variable and integrating we get
Solve (x – y)2 = a2
Put x – y = u then
∴ Eqn. (i) transform to u2(1 – ) = a2
Solve y dx – x dy + 4x3 y2 ex4 dx = 0.
The given differential equation can be written as
This is in general solution of the given D.E.