Worked out examples
Q.

The chief constituent in eucalyptus oil is a substance called eucalyptol, which contains 77.87% of C, 11.76% of Hydrogen and 10.37% of Oxygen

(a) What is the empirical formula for this substance?
(b)The mass spectrum of eucalyptol shows a peak at about 154 amu. What is the molecular formula ?

Sol.

(a) We now have the different compositions of ‘C’, ‘H’ and ‘O’ present in the sample.

In a chemical formula, the subscripts represent the ratio of number of moles of each element that combine to form one mole of the compound.
If we assume exactly 100g sample of the compound we know the mass of each element in the compound.
Assume that we have 100g of eucalyptol containing 77.87 grams of carbon, 11.76 grams of Hydrogen and 10.37grams of oxygen. As subscripts represent the mole ratio, we need to convert the grams of each element to moles. The conversion factor needed is the molar mass of each element.
Let n represent the number of moles of each element so that
Now we arrive at a formula C6.483H11.66O0.648. But as the chemical formulas are written in whole numbers we have to make this real numbers to whole numbers.For this convert the real numbers to whole number divide all the numbers by smallest subscript(0.648)
Now the emperical formula for eucalyptol is C10H18O
Structure of Eucalyptol

(b) As the mass spectrum of eucalyptol shows a peak at about 154 amu.
Now the weight of
C10H18O = 10 × 12.01 + 18 × 1.008 + 1 × 16.00
= 120.1 + 18.144 + 16
= 154.244
Hence molecular formula wt = 154.244
Molecular formula is C10H18O